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1

an=(2)^{n-1}

n | n-1 | 2^{n-1}

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1 | 0 | 1

2 | 1 | 2

3 | 2 | 4

4 | 3 | 8

5 | 4 | 16

Note that you did not write the sequence as (2)^{n-1.} You wrote it as (2)^n^-1, where n^{-1} = 1/n^{1} = 1/n. (The superscript feature of this editor does not express a power raised to a power.) However, if this was the intent, then instead of the above we would actually have:

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