Sarika Z.

asked • 08/29/16

Percentage problems

in a factory X out of every Y items produced were found to be defective. If 5% of the items produced during the day were defective, what was the total number of items produced that day? 

Mark M.

Information is incomplete. You say 5% were defective. How many was that?
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08/29/16

Sarika Z.

I'm sorry but this is all the information the question has. And the answer is 2000x/y and I can't comprehend the solution at all 
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08/29/16

Sarika Z.


the solution in the book goes like this.
if for every y items X is defective so for 100 items (100x)/y defective. So if 5%=(100x)/y
100%=(100x*100)/5y =2000x/y
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08/29/16

Sarika Z.

OH AND THE ANSWER WILL BE IN TERMS OF X AND Y 
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08/29/16

1 Expert Answer

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Rebecca H. answered • 08/29/16

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Algebra 2, Geometry, Trigonometry, and Precalculus

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Since X is 5% of Y, we can write a mathematical statement to represent the situation, though as Mark says, it cannot be solved without more information.
 
X is 5% of Y --> X=.05Y
Solve for Y.
X/.05=Y
Since .05=5/100=1/20, you can multiply X/(1/20) by 20/20 (a form of 1) and get:
20X=Y
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Sarika Z.

But the answer (2000x)/y 
the solution in the book goes like this. 
if for every y items X is defective so for 100 items (100x)/y defective. So if 5%=(100x)/y
100%=(100x*100)/5y =2000x/y 
Report

08/29/16

Sarika Z.

Hi! The answer says 2000x/y. :/ and this is all the information the question has 
Report

08/29/16

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