Word problem plz><

Question

The percent of maintenance: 14% 

The percent of instruction: 70%

if the cost of maintenance had been 50percent less and the amount saved had been applied to instruction,theN The increase in the expenditures for instruction would be what percent of the actual expenditures for Instruction?

Answer 1

The costs are percentages of some unknown value X, so  

 

cost of maintenance = 14% of X = 0.14*X  

cost of instruction = 70% of X = 0.70*X  

 

50 percent of 0.14*X is 0.07*X, so if the cost of maintenance had been 50 percent less then 0.07*X would have been applied to instruction.  This would be an increase of (0.07*X) / (0.70*X) = 0.10 = 10% of what was actually spent for instruction.