tan(-120°) = √3
Arctan(tan(-120°) = Arctan(√3)
The range of the Arctangent function is (-π/2, π/2)
So, Arctan(√3) = π/3, since π/3 is in the interval (-π/2, π/2) and
tan(π/3) = √3
Emma R.
asked • 08/22/16Evaluate this equation:
Arctan[tan(-120°)]
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2 Answers By Expert Tutors
Chunli M. answered • 08/22/16
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Arctan[tan(-120°)] = -120
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