Mark O. answered 05/28/16
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Hi Bianca,
X - XA = D
XI - XA = D, where I is the n x n identity
Factor out X out front.
X(I - A) = D
Assuming I - A is invertible, right multiply each side of the last equation by its inverse.
X(I - A)(I - A)-1 = D(I - A)-1
(I - A)(I - A)-1 = I
So, XI = D(I - A)-1
Or
X = D(I - A)-1