two vectors have magnitudes of 5.2 and 7.3. The dot product of the vectors is 20. what is the angle between the vectors?

Question

 I need help with this question

Answer 1

cos θ = dot product / (product of their magnitudes) so θ = cos^-1(20/(5.2×7.3)); you can feed this command to your calculator and get the answer (be sure to get into degree mode, first).

Answer 2

Angle between two vector= x

 

 

Angle between two vector is given by

 

cos x = U.V / |U| |V|   =

 

         = dot product of two vector / product of magnitude of vector

         =20/(5.2)(7.3)

        =0.5269

 

x = cos^-1 0.5269

  

  = 58.20

 

 

So angle between 2 vector is 58.20