
Kenneth S. answered 05/09/16
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Calculus will seem easy if you have the right tutor!
ANTIDIFFERENTIATING f" gives f'(x) = 4x2 -5cosx + C
f'(0) = 2 = 4(22) - 5 cos 0 + C
2 = 16 - 5 + C so C = -9.
Antidifferentiating f' gives (4/3)x3 - 5 sinx - 9x + K
f)0) = 2 = K
Final answer: f(x) = (4/3)x3 - 5sinx - 9x +2