
Arturo O. answered 06/06/16
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dA/dt = -0.3A
Separate the variables:
dA/A = -0.3dt
Integrate both sides:
ln(A) = -0.3t + ln(C), where C = unknown constant
Take e^() on both sides:
A(t) = Ce^(-0.3t)
Let A(0) = 0.10
Let A(T) = 0.05, where T = time when A drops by half (i.e. from 0.10 to 0.05)
A(T) / A(0) = 1/2
A(T) / A(0) = [Ce^(-0.3T)] / [C] = 1/2
e^(-0.3T) = 1/2
T = ln(1/2) / (-0.3) = 2.310 time units
No units were given for k, but k must have units of (time units)^(-1), such as sec^-1, min^-1, etc.
Note we answered the question without having to find the value of C.