
John R. answered 04/29/16
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Y= ce^kt
Sub in 300= ce^4k
100= ce^2k
Divide to get 3= e^2k
Take log of both sides ln3= 2k lne
So k=ln3/2
We now have y=ce^(ln3/2)t
Sub in to solve for t
100= ce^ln3
c=100/3
A Equation is y=100/3 e^(ln3/2) t
B At t=0 there were approx 100/3 or 33 filies.
C After 10 days there will be 100/3 e^(ln3)/2 *10 or approx 8100 flies.
Kathryn H.
04/29/16