What is the maximum value and/or minimum value of the quadratic function f(x)= - 5x^2-10x6??

Hi Kevin;

f(x)= -5x

^{2}-10x^{6}The fact that both x values are to an even exponential (2 and 6), means that the results of any value of x will be positive, whether or not x is negative.

Henceforth, 0 is the minimum value of the results of x...

f(x)=-5(0

^{2})-10(0^{6})f(x)=0

However, both the 5x

^{2}and 10x^{6}are being subtracted. Henceforth, the results of the whole equation will always be negative except when x=0.0 is

**maximum**value of f(x), while 0 is the**minimum**value of x to either exponential.There is no

**minimum**value of f(x) because there is nothing else restricting the value of x.
## Comments

I meant student posted quadratic function f(x) = -5x^2 - 10x - 6

but you gave the answer for 6th power polynomial function max f(x) = 0 with min x = 0 , but there is no minimum for "x" whatsoever for those functions.

x-6x6-6and f(x)= - 5x^2-10x6, within the context of his other questions, you will see that the latter is consistent. He is not yet studying parabolas, lines of such symmetry, vertexes, etc.