Charles C. answered 03/20/16
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To minimize labor costs, we want the optimal mix of level I and level II workers. This way we will stay within our desired hours constraint and also produce our desired number of items per week.
Let m be the hours used by level I workers
Let n be the hours used by level II workers.
From the problem, we know
So m + n >= 2600
15m + 22n >= 45000
So n= 2600 - m
Plug in: 15m+ 22(2600-m) > 45000
15m+ 22*2600 - 22m > 45000
We want to solve this equation and get m. Then plug into m + n = 2600 to get n. This will give you the hours needed for each skill level.
Let's continue to solve the above equation
15m -22m > 45000 - 22*2600
-7m > 45000 - 22*2600
-7m > -12200
when we divide by a negative number, we flip the inequality too
So m < -12200 / -7
The negative signs cancel, we get m < 1742.85
So we round down to the nearest whole number, and get m = 1742
We go back to m + n = 2600
1742 + n = 2600
n = 2600 - 1742
n = 858
So m is 1742 hours weekly, and n is 858 hours weekly.
We can also check our work with the equation
15m + 22n >= 45000
The left hand side is 15*1742 + 22*858
26130 + 18876
45006
This is at least 45000, so our answer is correct.