What is the 14th term of the geometric sequence: 3, 9, 27, 81,...

Question

I need help please 

Answer 1

For a geometric sequence, any term, a_n, may be computed as:

  a_n = ar^{(n – 1)}

 

where:

    a = a₁

    r = common ratio

 

For this problem,  a=3   and   r=3, so:

   a₁₄ = 3*3¹³     or 3¹⁴   or    4782969

Answer 2

Looks like this series is 3^1, 3^2, 3^3, 3^4... 

 

So in general a term in this series is 3^n where n is 1 in the first term, n is 2 in the second term, n is 3 in the third term, etc 

 

So you want to evaluate what 3^n is for the 14th term. n =14 for this term

 

So 3^14 

 

 

Answer 3

HI Darwin, this sequence is: 3¹, 3², 3³, ... 3¹⁴.

 

Use a calculator to find 3 raised to the 14 power.

 

Questions?