Thomas E. answered 01/19/16
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Let x = amt of the 40% alloy and 120-x =amt of the 80% alloy
.40(x) + .80(120-x) = .70(120)
-.40(x) + 96 = 84
-.4x = -12
x = 30kg of 40% alloy, 90kg of 80% alloy