Don L. answered 12/11/15
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi Meghan, this is a problem that compares areas.
Given:
Area = Length * Width
Let x represent the width of the original screen.
Then x + 2 represents the length of the original screen.
A = x * (x + 2)
A = x2 + 2x
Now increase the length by 1, or x + 3 is the new length. Increasing the length by one increases the area by 10 square inches.
Using the area formula again:
A + 10 = x * (x + 3)
Subtract 10 from both sides:
A = x2 + 3x - 10
The two areas are equal in size. Then:
x2 + 2x = x2 + 3x - 10
The x2 terms cancel out, leaving:
2x = 3x - 10
Subtract 2x from both sides:
0 = x - 10
Add 10 to both sides and rearrange:
x = 10
The length and with of the original screen:
The width is 10 inches.
The length is 12 inches.
Check:
Area of original screen:
A1 = 12 * 10 = 120 square inches.
Area of increased screen:
Length of increased screen is x + 3, or 13 inches.
A2 = 13 * 10 = 130 square inches.
A2 is 10 square inches larger than A1.
Questions?