
David W. answered 11/21/15
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If the circle touches each side of the square (at the middle of each edge), then the diameter of the circle is the same length as a side of the square. We can use the Pythagorean Theorem to determine the length of the diagonal of the square, but it is good to remember a set of "Pythagorean Triples" -- n*1, n*1, n*SQRT(2); these are the sides of a 45°-45°-90° triangle (half of the square)
The area of the circle is: 81 cm2 = ∏r2 = ∏(d/2)2 (note that radius = diameter/2)
(81)*(4/∏) = d2
d = SQRT(324/∏)
Now, the diagonal of the square (call it x) is: SQRT(324/∏)*SQRT(2)
x = SQRT(648/∏)
x ≈ 14.36 cm


David W.
Sometimes variables are not a mnemonic as we would like.
"find the diaginal of the square"
d = diameter of circle (also side length of square)
x = diagonal of square (1*SQRT(2) the side)
Do you still disagree?
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11/21/15
Mark M.
11/21/15