Find the antiderivative

Question

∫coshx/e^x dx

Answer 1

coshx = (e^x+e^-x)/2

 

So, coshx/(e^x) = 1/2 + (1/2)e^-2x

 

Therefore, ∫[coshx/(e^x)dx = ∫[1/2 + (1/2)e^-2x]dx

 

                                         = (1/2)x - (1/4)e^-2x + C