∫(2√x)/(√x) dx
Note that √x = x1/2. Now let u = x1/2:
- du = (1/2)x-1/2 dx = (1/2u) dx.
- Hence 2u du = dx.
Now substitute:
∫(2u/u) 2u du = 2 ∫ 2u du
Note that 2u = eln(2^u) = euln(2)
2 ∫ euln(2) du = (2/ln(2))*euln(2) + C = (2/ln(2))*2u + C = (2/ln(2))*2√x + C
Where C is the constant of integration.