
Jordan K. answered 10/29/15
Tutor
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(79)
Nationally Certified Math Teacher (grades 6 through 12)
Hi Tan,
For "at least" and "at most" combination problems - it's easier to start with the total possible combinations and then subtract the cases we don't want:
1. Total Possible Combinations:
52C4 (52 cards taken 4 at a time)
2. Three Hearts (unwanted case to subtract):
13C3 x 39C1 (13 hearts taken 3 at a time multiplied by 39 non-hearts taken 1 at a time)
3. Four Hearts (unwanted case to subtract):
13C4 (13 hearts taken 4 at a time)
Putting it all together, we have our counting formula for this problem, which we can use to calculate our answer:
Total Combos - (3-heart combos + 4-heart combos)
52C4 - ((13C3 x 39C1) + 13C4)
270,725 -((286 x 39) + 715)
270,725 - (11,154 + 715)
270,725 - 11,869
258,856 4-card hands with at most 2 hearts
Thanks for submitting this problem and glad to help.
God bless, Jordan (Romans 5:8)


Jordan K.
Good question - must have been thinking of 5-card draw poker !!
Answer has been corrected to start with 4-card hands.
Thanks for the catch.
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10/29/15
Arnold F.
10/29/15