Kevin W. answered 11/03/15
Tutor
5
(1)
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Take a systematic approach. If you start with a certain amount of money, xinitial. The money receives a 2% interest rate every year which is compounded monthly (12 times a year). So after the first month he has x1 month dollars in his account given by
x1 month = xinitial*(1+0.02/12months) = xinitial*(1.001666)
Note that 0.02 comes from 2%, meaning 2/100 = 0.02; and 0.001666 comes from 0.02/12 months = 0.001666 per month which is what the interest is when compounded for the month.
For the second month,
x2 month = x1 month*(1.001666) = xinitial*(1.001666)2
For the third month,
x3 month = x2 month*(1.001666) = xinitial*(1.001666)3
And so on until month 6 which is
x6 month = xinitial*(1.001666)6
Now the interest rate changes for month 7 to 3% so instead of 0.001666, the interest is 0.03/12 = 0.0025 every month. So for month 7
x7 month = x6 month*(1.0025) = xinitial*(1.001666)6*(1.0025)1
This leads to the 12th month when another increase happens to the interest from 3% to 4%. So month 12 has
x12month = xinitial*(1.001666)6*(1.0025)6
The 6 in the exponent next to the 1.001666 and 1.0025 denotes how many months the interest rate was applicable. Now instead of 0.0025 per month it is 0.04/12 = 0.003333 so at 18 months you have
x18 month = xinitial*(1.001666)6*(1.0025)6*(1.003333)6
and at 21st month when the interest is raised to 5% for the last 3 months, the equation is
x21 month = xinitial*(1.001666)6*(1.0025)6*(1.003333)6*(1.004166)3
Now solve for xinitial knowing that x21 month is $4,300.