write the complex number in standard form?

Question

write the complex number in standard form: (3-2i)^2(3+2i)

                                                              ---------------------

                                                                       (5-i)

 

Step by step would be great! I have a test tomorrow that I have to take a day early and I need to learn this stuff!

thank you!

-Addie

Answer 1

 

(3-2i)^2(3+2i) = (3-2i)(9+4) = 13(3-2i), since (3-2i)(3+2i) = 9+4

1/(5-i) = (5+i)/26

So,

 

(3-2i)^2(3+2i)/(5-i)

= 13(3-2i)(5+i)/26

= (1/2)(15+2 +3i-10i)

= (17/2) - (7/2)i <==Answer