Mark M. answered 09/15/15
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
s represents score on first test
1.03(s) represents score on the second test
(1.03)(1.03)(s) represents score on third test
(1.03)(1.03)(1.03)(s) represents score on fourth test
(1.03)(1.03)(1.03)(1.03)s represents score on fifth test
Simplifying
s represents score on first test
1.03s represents score on second test
1.0609s represents score on third test
1.092727s represent score on fourth test
1.12550881s represents score on fifth test
Now to the average. The fifth score is "twice as much as the first four."
This means that a total of 12 scores are used - the first 4 and the 2(4) for the fifth.
The sum of the first four
5.30913581s
Eight times the fifth
8(1.12550881)s
9.00407048s
The sum of the 12 test scores
14.3132063s
14.3132063s = 12(79)
14.3132063s = 948
s ≈ 66.2325394
The score on the fifth exam was approximately
1.12550881(66.2325394)
74.5453
This number is less than the average. I need some time to go over my calculations.