Evaluate the limit, if it exisit lim goes to 0 of (1/t)-(1/t^2+t)

Question

Please help me

Answer 1

lim_t→0 [1/t - 1/(t²+t)]

 

= lim_t→0 [(t+1)/(t²+t) - 1/(t²+t)]

 

= lim_t→0[t/(t²+t)]

 

=lim_t→0 1/(t+1)

 

= 1/(0+1)

 

= 1