GH=7y+3HI=3y-5 GI=9y+7

Question

I need help with this problem it really confuses me! PLEASE Help! Thank you so much. I appreciate it. LOL.

Answer 1

assuming the points are in this order: G----------H------I

(7y+3)+(3y-5)=(9y+7)

10y-2=9y+7

10y-9y=7+2

y=9

GH=7*9+3=66

HI=3*9-5=22

GI=9*9+7=88

 

Answer 2

Assuming that the point G, H, and I are collinear, G and I are the end points and H is somewhere between them.

Draw a picture.

GH + HI = GI substitute
7y + 3 + 3y - 5 = 9y + 7 combine like terms
10y - 2 = 9y + 7 subtract 9y from both sides
y - 2 = 7 add 2 to both sides
y = 9

GH = 7y + 3
GH = 63 + 3
GH = 66

HI = 3y - 5
HI = 27 - 5
HI = 22

GI = 9y + 7
GI = 81 + 7
GI = 88

Check

GH + HI = GI
66 + 22 = 88