I was absent today, and I don't know how to do these kinds of problems. Help me solve.

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Grigori S. | Certified Physics and Math Teacher G.S.Certified Physics and Math Teacher G.S.

Whatever line you have its equation in the slope-intercept form is

y = mx + b (1)

where "m" stands for the slope and "b" stands for the vertical interecept. You can find the slope and "b" for any particular line by an additional information, such as points the line is passing trough, or if you are given the equation for the same line in the stndard from:

ax + by = c (2) ("b" here is not supposed to be the same as in (1))

To write this equation in the slope - intercept form, you have to separate variables. x and y. If you subtract ax from both sides and then divide by b, you will obtain

y = -(a/b)x + c/b (3)

In this case the slope is "-(a/b)" and the intercept is "c/b". If you have any other question let me know,

Good luck!

The slope intercept form for the equation of a line is:

y = mx + b, where m is the slope of the line.

This format derives its name, slope intercept, from the fact that b is the intercept on the y-access when x = 0.

This should not be confused with the point-slope format for the equation of a line which is

y - y1 = m(x - x1), where (x1,y1) is a known point on the line, m is the slope of the line, and (x,y) is any other point on the line.

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