Donna I. answered 08/02/15
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Teaching experience through grad Econ and undergrad Math/Statistics
I can't see the function, but the mean value says that if the function (f) is continuous (no holes or jumps) on a closed interval,[1,9] , then the slope of the secant line, (f(9)-f(1))/(9-1) is equal to the derivative somewhere on that interval. In other words, if the function is continuous, plug 9 and 1 into the function to get f(9) and f(1). Calculate (f(9)-f(1))/(9-1) and set that equal to the derivative, f'(c). Finally solve for c. It should be between 1 and 9.