Not sure where to start :/?

Question

1+x< 3x-3 <4x-2

Answer 1

Not sure if you are supposed to solve for x in the inequality, or graph the answer or what... doesn't state. 

 

But... let's work on the inequality itself

 

1+x<3x-3<4x-2

 

Look at this initially as 2 separate inequalities

 

1+x<3x-3     and      3x-3<4x-2

 

for 1+x<3x-3

     subtract x from both sides

     1<2x-3

     Add 3 to both sides

     4<2x

    Divide both sides by 2

     2<x

    or...  x>2

 

For 3x-3<4x-2

      subtract 3x from both sides

      -3<x-2

       add 2 to both sides

       -1 < x    or    x>-1

 

We have two inequalities again:   x>2  and  x>-1

 

The area where both statements are true is where x>2

 

If you need to graph this answer then, on a Cartesian coordinate plane,

draw a dashed vertical line at x=2 (dashed to show the line is not included because

x>2  not  x≥2)  then shade everything to the right of the dashed line