Inactive Tutor answered 05/29/15
Tutor
New to Wyzant
This is solved by creating two algebraic equations and solving for a common x.
You know that each method requires the one-time costs plus the variable costs. Therefore, the two methods can be expressed as:
y=21390+20.25x
and
y=47466+10x, with y representing the total cost for a given x (x represents the number of books).
You also know that the costs must be equal to each other, so:
21390+20.25x=y=47466+10x
21390+20.25x=47466+10x
Now, all you have to do is solve for x.
Combining like terms and getting x by itself,
20.25x-10x=47466-21390
10.25x=26076
x=26076/10.25
x=2544
So, the costs of these two methods will be equal if they both make 2544 books.
To check, plug 2544 back into both equations for x and you should get the same number.
y=21390+20.25(2544) y=47466+10(2544)
y=21390+51516 y=47466+25440
y=72906 y=72906