Michael J. answered • 05/19/15
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Mathematical Reasoning and Logic Application
When we graph inequalities, we are looking for the restricted region.
4x + 6y ≤ 12 ; y ≥x , x ≥ 0 , y ≥0
First, we want to turn this inequality into y≤mx+b form.
Subtract 4x on both sides of inequality.
6y ≤ -4x + 12
Divide both sides of inequality by 6.
y ≤ (-2/3)x + 2
Shade the regions below and on the line (-2/3)x + 2 , above and on the line y=x, and in the first quadrant. The shaded region that meets these restrictions is the solution.
Do the same to the second problem.
Michael J.
For which equation are you referring to?
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05/19/15
Haley N.
y≥x. That is one of the four equations listed above
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05/19/15
Michael J.
y ≥ x is actually an inequality because it has a comparison symbol rather than an equal sign.
when
x=2 and y=3,
we actually have a coordinate point. This coordinate point is in the form (x,y). Therefore, the coordinate is (2, 3). You can still graph the inequality y≥x , but there will be no shaded region since 2 and 3 are actual values of x and y.
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05/19/15
Michael J.
Hold on, I made an error in my last comment. You CANNOT graph this inequality because your other restrictions do not have any ranges. They are exact values, and therefore do not have any boundaries to shade.
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05/19/15
Haley N.
05/19/15