Johnny B.
asked • 05/05/15how do you solve a rational equation
√4z+1=3+√4z-2
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1 Expert Answer
Mark M. answered • 05/05/15
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
Square both sides
4z + 1 = 9 + 4z - 2 + 6√(4z - 2)
4z + 1 = 7 + 4z + 6√(4z - 2)
1 = 7 + 6√(4z - 2)
-6 = 6√(4z - 2)
-1 = √(4z - 2) square both sides
1 = 4z - 2
3 = 4z
3/4 = z
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Nathan B.
05/05/15