Inactive Tutor answered 11/03/24
Tutor
New to Wyzant
xy = √2; x2 + y2 = 3; (x + y)2 = 3 + 2√2; x + y = √(3 + 2√2) = √2 + 1
(x - y)2 = 3 - 2√2; x - y = √(3 - 2√2) = √2 - 1; x = √2; y = 1
Margaret B.
asked 04/15/15Inactive Tutor answered 11/03/24
xy = √2; x2 + y2 = 3; (x + y)2 = 3 + 2√2; x + y = √(3 + 2√2) = √2 + 1
(x - y)2 = 3 - 2√2; x - y = √(3 - 2√2) = √2 - 1; x = √2; y = 1
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