Raymond B. answered 05/04/23
Tutor
5
(2)
Math, microeconomics or criminal justice
r = 3(4-2cosT)
4r -2rcosT = 3
4sqr(x^2+y^2) -2x =3
16x^2 +16y^2 -2x =3
16x^2 +16(y^2 -x/8 + 1/16^2)= 3 + 16/256
16x^2 + 16(y^2 - 1/16) = 16/256 +3= 784/256
x^2 + (y^2 -1/16) = 784/256
is a circle with center (0, 1/16)
radius = (sqr784)/16
circles don't have directrices