
Leo W. answered 06/13/24
Tutor
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Mathematica spoken here
The primary solution for 2x would fall in quadrant 4, meaning x will be in quadrant 2. However there are actually infinite solutions, 2x = Arctan(-24/7) +/- k pi. Thus x = Arctan(-24/7)/2 +/- k pi/2, giving solutions in every quadrant.