Inactive Tutor answered 06/13/24
Tutor
New to Wyzant
The primary solution for 2x would fall in quadrant 4, meaning x will be in quadrant 2. However there are actually infinite solutions, 2x = Arctan(-24/7) +/- k pi. Thus x = Arctan(-24/7)/2 +/- k pi/2, giving solutions in every quadrant.