Write the expression as x2ex^3 if that is what you mean. As you wrote it, x2(ex)3 = x2e3x which is not solved by substitution, but by integration by parts twice.
2 Answers By Expert Tutors
Let u = x3. So, du = 3x2dx. Therefore, x2dx = (1/3)du
∫x2(ex)3dx = (1/3)∫eudu = (1/3)eu + C = (1/3)(ex)3 + C
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