The length of a rectangle is triple the width decreased by 5. Find the dimensions of the rectangle if it has an area of 112 cm

Answer 1

L =3W -5

LW = 112

(3W-5)W = 112

3W^2 -5W -112 =

use the quadratic formula

W =5/6 +/-(1/6)sqr(25+4(3)(112))

W = 5/6 +/-(1/6)37

W = (5+37)/6 = 42/6 = 7 cm wide

L = 3W-5 = 3(7)-5 = 21-5 = 16 cm long

dimensions are 7 by 16 centimeters