Logarithmic equation

Question

log 4x+6 - log x = 3+1

Answer 1

log 4x+6 - log x = 3+1 . use laws of logarithms

log ((4x+6)/x) = 4 . put in exponential form

10⁴ = (4x + 6)/x

10000x = 4x + 6 you should be able to finish solving this equation..