Length = 38 inches
Width = 19 inches
Area = 38(19) = 722 in^2
L = 4w-38 = 4(19)-38= 38
722 = LW = (4W-38)(W)
4W^2 -38W -722 =0
factor
(4W-38)(W-19) =0
W=19 = width
L=4W-38=4(19)-38= 38 Length
Cass M.
asked 06/11/22A rectangle has a length of 38 inches less than 4 times the width. If the area of the rectangle is 722 square inches, find the length of the rectangle.
Length = 38 inches
Width = 19 inches
Area = 38(19) = 722 in^2
L = 4w-38 = 4(19)-38= 38
722 = LW = (4W-38)(W)
4W^2 -38W -722 =0
factor
(4W-38)(W-19) =0
W=19 = width
L=4W-38=4(19)-38= 38 Length
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