Inactive Tutor answered 11/18/21
p = 50 - 0.005x2 = 32; x = - 18/(- 0.005) = 3600; x = 60
CS = ∫060(50 - 0.005x2 - 32)dx = (18x - 0.005x3/3)060 = 720
Jake L.
asked 11/18/21For the price-demand equation p = 50 − 0.005x^2 , the consumers’ surplus at a price level of 32 is equal to the area of the region labeled CS in the figure. Find this area using integration. You’ll need to solve for x0 first.
Inactive Tutor answered 11/18/21
p = 50 - 0.005x2 = 32; x = - 18/(- 0.005) = 3600; x = 60
CS = ∫060(50 - 0.005x2 - 32)dx = (18x - 0.005x3/3)060 = 720
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