Inactive Tutor answered 11/02/21
Tutor
New to Wyzant
f(x) = x3; f(3) = 33 = 27; f'(x) = 3x2; f'(3) = 3·32 = 27;
L(x) = 27 + 27(x - 3); L(x) = 27x - 54;
(3.0001)3 ≈ L(3.001) = 27·3.001 - 54 = 27.027
Clayton M.
asked 11/02/21Inactive Tutor answered 11/02/21
f(x) = x3; f(3) = 33 = 27; f'(x) = 3x2; f'(3) = 3·32 = 27;
L(x) = 27 + 27(x - 3); L(x) = 27x - 54;
(3.0001)3 ≈ L(3.001) = 27·3.001 - 54 = 27.027
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