find h'(3) when h(x)=f(x)/g(x)

Question

suppose that f(x) and g(x) are differentiable functions such that f(3)=-2, f'(3)=6 , g(3)=9 and g'(3)=5.

Answer 1

h' = (gf'- fg')/g^2

h'(3) = (9(6)- (-2)(5)/9^2 = (54+10)/81

h'(3) = 64/81 = about 0.79