
Bradford T. answered 04/27/21
Retired Engineer / Upper level math instructor
Rev(t) = ∫R(t)dt = 0.41t2+1.14t + C
Rev(0) = 5.9 = 0+0+C -->> C = 5.9
Rev(t) = 0.41t2+1.14t + 5.9
For 2012, t = 8
Rev(8) = 26.24+9.12+5.9 = 41.26 billions of dollars
Ryan N.
asked 04/27/21U.S. Internet advertising revenue grew at the rate of
R(t) = 0.82t + 1.14 (0 ≤ t ≤ 4)
billion dollars/year between 2002 (t = 0)
and 2006 (t = 4).
The advertising revenue in 2002 was $5.9 billion
Bradford T. answered 04/27/21
Retired Engineer / Upper level math instructor
Rev(t) = ∫R(t)dt = 0.41t2+1.14t + C
Rev(0) = 5.9 = 0+0+C -->> C = 5.9
Rev(t) = 0.41t2+1.14t + 5.9
For 2012, t = 8
Rev(8) = 26.24+9.12+5.9 = 41.26 billions of dollars
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