
Sidney P. answered 04/28/21
Astronomy, Physics, Chemistry, and Math Tutor
I believe you integrate R'(x) with limits of zero and 150: R(150) = ∫0150 (-0.1x + 40)dx = [-0.05x2 + 40x]0150 = $7125.
Ryan N.
asked 04/27/21The management of Ditton Industries has determined that the daily marginal revenue function associated with selling x units of their deluxe toaster ovens is given by the following, where R'(x) is measured in dollars/unit.
R'(x)=-0.1x+40
Sidney P. answered 04/28/21
Astronomy, Physics, Chemistry, and Math Tutor
I believe you integrate R'(x) with limits of zero and 150: R(150) = ∫0150 (-0.1x + 40)dx = [-0.05x2 + 40x]0150 = $7125.
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