f(x) = 6ex - x is positive and continuous on the interval [3,9].
Area below the graph of f(x) and above the x-axis = ∫(from 3 to 9) [6ex - x]dx = [6ex - (1/2)x2](from 3 to 9) =
(6e9 - 81/2) - (6e3 - 9/2) = 6(e9 - e3) - 36
Ryan N.
asked 04/27/21Find the area (in square units) of the region under the graph of the function f on the interval [3, 9].
f(x)=6e^x-x
f(x) = 6ex - x is positive and continuous on the interval [3,9].
Area below the graph of f(x) and above the x-axis = ∫(from 3 to 9) [6ex - x]dx = [6ex - (1/2)x2](from 3 to 9) =
(6e9 - 81/2) - (6e3 - 9/2) = 6(e9 - e3) - 36
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