
Yefim S. answered 04/27/21
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Area A = ∫-12(- x2 + 5)dx =(- x3/3 + 5x)-12 = (- 8/3 + 10) - (1/3 - 5) = 15 - 3 = 12.
Ryan N.
asked 04/27/21Find the area (in square units) of the region under the graph of the function f on the interval [−1, 2].
f(x)=-x^2+5
Yefim S. answered 04/27/21
Math Tutor with Experience
Area A = ∫-12(- x2 + 5)dx =(- x3/3 + 5x)-12 = (- 8/3 + 10) - (1/3 - 5) = 15 - 3 = 12.
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