
Yefim S. answered 04/22/21
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5
(20)
Math Tutor with Experience
Δx = (10 - 0)/5 = 2; n = 5
R5= L5 = ∑i = 04[4e^(- 2i)]·2 = ∑i = 048e^(- 2i) = 9.251721095
Ryan N.
asked 04/22/21If using the tabular method, values of the function in the table should be accurate to at least five decimal places.)
f(x)= 4e^-x over [0,10], n=5
Yefim S. answered 04/22/21
Math Tutor with Experience
Δx = (10 - 0)/5 = 2; n = 5
R5= L5 = ∑i = 04[4e^(- 2i)]·2 = ∑i = 048e^(- 2i) = 9.251721095
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