Inactive Tutor answered 04/13/21
Tutor
New to Wyzant
f'(x) = 6x^2+6x-2
f(x) = 2x^3 + 3x^2 -2x + c where c= a constant
f(2) = 7 = 16+12-4 + c
c = 7-24 = - 17
f(x) 2x^3 +3x^2 -2x -17
Ryan N.
asked 04/13/21f '(x) = 6x2 + 6x − 2; f(2) = 7
Inactive Tutor answered 04/13/21
f'(x) = 6x^2+6x-2
f(x) = 2x^3 + 3x^2 -2x + c where c= a constant
f(2) = 7 = 16+12-4 + c
c = 7-24 = - 17
f(x) 2x^3 +3x^2 -2x -17
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