
Yefim S. answered 03/26/21
Math Tutor with Experience
P'(x) = - 0.6x2 + 70 = 0; x2 = 70/06; x = √(70/06) = 11 units.
Now, P''(x) = - 1.2x; P''(11) = -1.2·11 = - 13.2 < 0. So, at x = 11 we have maximum profit
Ryan N.
asked 03/26/21the marginal profit (in dollar per unit) when x units are produced and sold is given by p'(x)= -0.6x^2+70. The number of units that must be produced and sold to make the profit a maximum is:
Yefim S. answered 03/26/21
Math Tutor with Experience
P'(x) = - 0.6x2 + 70 = 0; x2 = 70/06; x = √(70/06) = 11 units.
Now, P''(x) = - 1.2x; P''(11) = -1.2·11 = - 13.2 < 0. So, at x = 11 we have maximum profit
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.