Edward C. answered 02/24/15
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Caltech Grad for math tutoring: Algebra through Calculus
For any linear function the domain and range are always all real numbers (-∞,∞).
For a quadratic the domain is always all real numbers.
To find the range of a quadratic you must find the vertex, which is located at x = -b/2a for a quadratic in standard form ax^2 + bx + c.
In this case the vertex is located at x = 4/(2*1) = 2
The value of the quadratic when x = 2 is
2^2 -4*2 - 5 = 4 - 8 - 5 = -9
a is positive so the quadratic opens upward, therefore the vertex is a minimum value, and the quadratic can take any value greater than or equal to the minimum.
So the range is y>= -9 or (-9,∞)