
Tim C. answered 10/03/20
former teacher and instructor of discrete math
If I'm reading your question correctly, this says that we need to show that you always have either A or D, given that you have both B and C any time you have A, and given that you have both D and E whenever you have B.
But it's possible for both the conditionals to be satisfied having neither A nor D. None of A,B,C,D,E could be true, for example. So your problem is either incomplete or false.