If a sample of C3H6 stored in a 2.95-L container at 10.6 atm and 25.0C is transferred to a 6.96-L container at 5.00atm, what is the resulting temperature?

Answer 1

C₃H₆ has two isomers, namely cyclpropane or propene. They are relatively close to ideal gas, except that propene may be intermolecular interaction between the double bonds of two molecules.

(Let me know if you want to learn more about basic Organic Chemistry)

This is a typical combined gas law problem.

PV/T = k OR P₁V₁/T₁ = P₂V₂/T₂ Where T is in Kelvin scale, such that K = 273 + °C.

Put in the values

(10.6 atm)(2.95 L) / (273 + 25.0)K = (5.00 atm)(6.96 L) / T₂

Cancelling the units:

(10.6 atm)(2.95 L) / (273 + 25.0)K = (5.00 atm)(6.96 L) / T₂ to give T₂ in K.

Rearranging the terms and resulting:

T2 = (5.00)(6.96)(298) / (10.6)(2.95) K

= 332 K

= 59 °C// answer

DO NOT forget to convert Celsius scale to Kelvin scale for temperature before you apply the combined gas law formula.

Why? you may ask. It is because an ideal gas behaviors become "zero" at absolute zero, not when water freezes/melts at STP. Under STP, there are still a lot of kinetic energy with an ideal gas.