Calculate the volume of N2 that results when 0.138 L of the gas is heated from 308.0 K to 351.0 K at 3.00 atm.

Answer 1

Nitrogen, N₂, is close to ideal gas due to minimum inter-molecular interaction between nitrogen molecules.

In order to find the volume, we have to assume the initial pressure is 1.0 atm.

Use combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

Put in the numbers:

(1.00 atm)(0.138L)/308.0K = (3.00 atm)V₂/351.0K

Cancel the units:

(1.00 atm)(0.138 L)/308.0 K = (3.00 atm)V₂/351.0 K

Solve to give V₂ = 0.0524 L // answer OR 52.4 mL //

You need to tie his kind of problem to real life examples. So you know how to make reasonable assumption.

Answer 2

The general relationship between volume and temperature at constant pressure is Charles's Law. It states that volume and temperature (in Kelvins) are proportional, so changes are also proportional, i.e. V₁/T₁=V₂/T₂.

So 0.138/308.0 K=V₂/351.0 K, solve for V₂=0.157 L. this makes sense because since they are proportional, if the temperature increases, the volume will increase.